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=-8:-2×6+12
=24+12
=36
x² - 4x
_______________
(x - 6) (2x - 2) + 12
x² - 4x
= _______________
(2x² - 14x + 12) + 12
x² - 4x
= _____________
2x² - 14x + 24
Pakai dalil L'Hospital
Turunkan atas dan bawah
2x - 4
= _________
4x - 14
2(4)- 4
= _________
4(4) - 14
8 - 4
= ______
16 - 14
= 4/2
= 2
Jadi, nilai limitnya adalah 2