Question

Diket: h(x) = (2-3x)^5 , maka turunan pertama h yaitu h'(1) = ....

Answer 1

Pertama, turunkan terlebih dahulu.
h(x) = (2 - 3x)⁵
=> h'(x) = 5(2 - 3x)⁴ * (-3)
=> h'(x) = -15(2 - 3x)⁴
Sekarang substitusi x = 1 ke h'(x),
=> h'(1) = -15(2 - 3)⁴
=> h'(1) = -15 * 1 = -15

Answer 2

H(x)= (2-3x)^5 jadi, h'(x)= 5(2-3x)^4 .-3 --------------> h'(x)= -15(2-3x)^4 ------> h'(1)= -15(2-3.1)^4 ---> h'(1)= -15.1= -15