Question

(-x² + 5y⁵)² =

(-2x + 4y)² =

(0,5x + ½y )²t =

Answer 1

(-x^{2}+5y^{2})^{2}=x^{4}+25y^{4}
(-2x+4y)^{2}=4x^{2}+16y^{2}
(\frac{1}{2}x+\frac{1}{2}y)^{2}*t=

=(\frac{1}{4}x^{2}+\frac{1}{4}y^{2})*t=\frac{1}{4}x^{2}t+\frac{1}{4}y^{2}t