Question

X + 5\4y = 10(x-y)
4\3(x-2y)+6y=1

Tolong dijawab ya saya pusing ama PR adek saya

Answer 1

X + 5\4y = 10(x-y)
x + 5/4 y = 10x - 10 y
x - 10x + 5/4 y + 10 y = 0
-9x + 45/4 y = 0 (dikali 4)
-36x + 45y = 0

4\3(x-2y)+6y=1
4/3 x - 8/3 y + 6y = 1
4/3 x + 10/3 y = 1 (dikali 3)
4x + 10y = 3

jika di cari nilai x dan y nya, maka :
-36x + 45y = 0 (dikali 1) -36x + 45y = 0
   4x + 10y = 3 (dikali 9)  36x + 90y = 27
                                    ----------------------- +
                                             135y = 27
                                                  y = 27/135 = 1/5
4x + 10(1/5) = 3
4x + 2 = 3
4x = 1
 x  = 1/4