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x + 2 ≠ 0
x ≠ -2
D = R \ {-2}
x² - 4 = 0
(x + 2)(x - 2) = 0
x = -2 ∉ D
x = 2
b)
x - 3 ≠ 0
x ≠ 3
D = R \ {3}
x - 3 = 0
x = 3 ∉ D
brak rozwiązania
c)
x - 2 ≠ 0
x ≠ 2
D = R \ {2}
x² - 4 = 0
(x - 2)(x + 2) = 0
x = 2 ∉ D
x = -2