Question

Rozwiąż

a) (x-3)/(2-x)=2

b) (4x-2)/(x+1)=(3x-4)/(x-1)

Answer 1

a) (x-3)/(2-x)=2 /*(2-x)

(x-3)=2*(2-x)

x-3=4-2x

3x=7

x=7/3

b) (4x-2)/(x+1)=(3x-4)/(x-1)

(4x-2)/(x+1)=(3x-4)(x-1)

(4x-2)*(x-1)=(x+1)*(3x-4)

4x^2-2x-4x+2=3x^2+3x-4x-4^2-5x+6=0

delta=b^{2}-4ac

delta=25 - 4*1*6= 1

x1=(5-1)/2=2

x2=(5+1)/2=3

 

* b^2=b do kwadratu

Answer 2

(x-3)/(2-x)/=2 /*(2-x)

(x-3)=2*(2-x)

x-3=4-2x

3x=7

x=7/3

 

(4x-2)/(x+1)=(3x-4)(x-1) (korzystając z proporcji mnożenie na krzyż)

(4x-2)*(x-1)=(x+1)*(3x-4)

4x^2-2x-4x+2=3x^2+3x-4x-4

x^2-5x+6=0

delta = 25 - 4*1*6= 1

x1=(5-1)/2=2

x2=(5+1)/2=3