Ιx-1Ι+3x=x²+2
x-1+3x=x²+2
-x²+4x-3=0
a=-1 b=4 c=-3
Δ=b²-4ac=4²-4*(-1)*(-3)=16-12=4
√Δ=2
x₁=(-b-√Δ)/2a=(-4-2)/(2*(-1))=-6/-2=3
x₂=(-b+√Δ)/2a=(-4+2)/(2*(-1))=-2/-2=1
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Ιx-1Ι+3x=x²+2
x-1+3x=x²+2
-x²+4x-3=0
a=-1 b=4 c=-3
Δ=b²-4ac=4²-4*(-1)*(-3)=16-12=4
√Δ=2
x₁=(-b-√Δ)/2a=(-4-2)/(2*(-1))=-6/-2=3
x₂=(-b+√Δ)/2a=(-4+2)/(2*(-1))=-2/-2=1