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(x³-1)²= (x³)²-2·x³·1+1²= x⁶-2x³+1
(x⁴+x)²=(x⁴)²+2·x⁴·x+x²= x⁸+2x⁴⁺¹+x²= x⁸+2x⁵+x²
(x⁵+x⁴)³= (x⁵)³+3·(x⁵)²·x⁴+3·x⁵·(x⁴)²+(x⁴)³= x¹⁵+3x¹°⁺⁴+3x⁵⁺⁸+x¹²= x¹⁵+ 3x¹⁴+3x¹³+x¹²
2x²+3²= 2x²+9 chyba że było (2x)²+3²=4x²+9