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p-A=x+ax
p-A=x(1+a) I: (1+a)
p-A:1+a= x
m=(X+1)p-3x
m=Xp+p-3x I+3x
m+3x=Xp+p I -m
3x=Xp+p-m I :3
x= Xp+p-:3
p-A=x+ax
p-A=x(1+a) I :(1+a)
p-A:1+a= x
m=(X+1)p-3x
m=Xp+p-3x I +3x
m+3x=Xp+p I -m
3x=Xp+p-m I :3
x= Xp+p-:3