Question

wyznacz x : proszę tez o wypisanie dziedzin. ;)

log

Answer 1

log₃x + ½*log₃x = 3

3/2*log₃x = 3         /*⅔

       log₃x = 3*⅔

       log₃x = 2

z def. log

       x = 3²

       x = 9

 

½log₅x - log₅x = -1

- ½log₅x  = -1            /*(-2)

     log₅x = 2

z def. log

      x = 5²

      x = 25

 

z def log.

 logπ z x = 2°

 logπ x = 1

z def. log

x = π¹

x = π

 

 

z def. log

log½ x  + 1 = 2²

log½ x = 4 -1

log½ x = 3

z def. log

x = (½)³

x = ⅛

 

z def. log

log₂(log₃x -1) = (√3 )°

log₂(log₃x -1) = 1

z def. log

log₃x -1 = 2¹

log₃x = 2 +1

log₃ x = 3

z def. log

x = 3³

x = 27

 

 

 

 

logx²  1 = 0

z def. log

1 = (x²)°

1 = x°

1  = 1 tozsamość

x ∈ R, bo x² jest zawsze dodatnie