Wyznacz x: Log4(2x-5)=-2 Proseze o pomoc
log4 (2x - 5) = -2
D: 2x - 5 > 0
2x > 5
D: x > 2,5
log4 (2x - 5) = log4 4^(-2)
2x - 5 = 4^(-2)
2x - 5 = 1/16
2x = 1/16 + 5
2x = 81/16
x = 81/16 * 1/2
x = 81/32 ∈ D
x = 2 i 17/32
log₄(2x-5)=-2
4⁻²=2x-5
1/16=2x-5
1=32x-80
32x=1+80
32x=81
x=81/32
x=2¹⁷/₃₂
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log4 (2x - 5) = -2
D: 2x - 5 > 0
2x > 5
D: x > 2,5
log4 (2x - 5) = log4 4^(-2)
2x - 5 = 4^(-2)
2x - 5 = 1/16
2x = 1/16 + 5
2x = 81/16
x = 81/16 * 1/2
x = 81/32 ∈ D
x = 2 i 17/32
log₄(2x-5)=-2
4⁻²=2x-5
1/16=2x-5
1=32x-80
32x=1+80
32x=81
x=81/32
x=2¹⁷/₃₂