f(x) = ax^2 + bx + c
x1 = 1, x2 = -2, A(2;-8)
szukane: a, b, c.
Wzór funkcji w postaci iloczynowej:
y = a(x-x1)(x-x2)
A(2;-8)
-8 = a(2-1)(2+2)
-8 = 4a /:4
a = -2
-------
Mamy więc:
y = -2(x-1)(x+2) = -2(x2 + 2x -x -2) = -2(x^2 + x -2)
y = -2x^2 - 2x + 4
---------------------
=====
b = -2
c = 4
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f(x) = ax^2 + bx + c
x1 = 1, x2 = -2, A(2;-8)
szukane: a, b, c.
Wzór funkcji w postaci iloczynowej:
y = a(x-x1)(x-x2)
A(2;-8)
-8 = a(2-1)(2+2)
-8 = 4a /:4
a = -2
-------
Mamy więc:
y = -2(x-1)(x+2) = -2(x2 + 2x -x -2) = -2(x^2 + x -2)
y = -2x^2 - 2x + 4
---------------------
a = -2
=====
b = -2
=====
c = 4
=====