Wyznacz współczynniki a i b tak, aby liczby -1 i 1 były pierwiastkami wielomianu w(x)=x3 +x2+ax+b
W(-1)=0
W(1)=0
W(x)=x³+x²+ax+b
0=(-1)³+(-1)²+a·(-1)+b
0=1³+1²+a+b
0=-1+1-a+b
0=1+1+a+b
0=b-a
-2=b+a
----------+
2b=-2
b=-1
a=-1
W(x)=x³+x²-x-1
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W(-1)=0
W(1)=0
W(x)=x³+x²+ax+b
0=(-1)³+(-1)²+a·(-1)+b
0=1³+1²+a+b
0=-1+1-a+b
0=1+1+a+b
0=b-a
-2=b+a
----------+
2b=-2
b=-1
a=-1
b=-1
W(x)=x³+x²-x-1