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F(x)=2x^2+bx-4
H(x)=x^3-7x^2+8x+5
W(x)-F(x)=H(x)
x^3+ax^2+3x+1-(2x^2+bx-4)=x^3-7x^2+8x+5
x^3+ax^2+3x+1-2x^2-bx+4=x^3-7x^2+8x+5
x^3+ax^2-2x^2+3x-bx+5=x^3-7x^2+8x+5
1x^3+(a-2)x^2+(3-b)x+5=1x^3-1x^2+8x+5
Porównujemy.
1=1
a-2=-1 czyli a=1
3-b=8 czyli b=-5