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a) 4x+2, 5x+1, 9x-2
b) 2x+1, x kwadrat-2x+8, 4x+3
w podanej kolejnosci tworzyly ciag arytmetyczny
a)
2(5x+1)=4x+2 + 9x-2
10x + 2 = 13x
3x=2
x=2/3
b)
2(x²-2x+8)= 2x+1 + 4x+3
2x²-4x+16-6x-4=2x²-10x+12=x²-5x+6=0
Δ=25-4*6=1
x₁=2 lub x₂=3