wyznacz wartość funkcji F(x)=-x^2-4x+1 dla x=3 razy piarwiastek z 2 -2
f(x)=x²-4x+1
f(3√2-2)=(3√2-2)²-4(3√2-2)+1
f(3√2-2)=18-12√2+4-12√2+8+1
f(3√2-2)=31-24√2
f(x) = -x² -4x +1
dla x = 3√2 -2
f(3√2 -2) = -(3√2 -2)² - 4( 3√2 -2) +1
Korzystam ze wzoru :
(a-b)²= a²-2ab+b²
f(3√2 -2) = -[(3√2)² - 2*3√2 *2 + 2² ] - 12√2 + 8 +1
f(3√2 -2) = -[ 9*2 - 12√2 +4] -12√2 +9
f(3√2 -2) = -[22 -12√2 ] -12√2 +9
f(3√2 -2) = - 22 +12√2 -12√2 +9
f(3√2 -2) = - 13
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f(x)=x²-4x+1
f(3√2-2)=(3√2-2)²-4(3√2-2)+1
f(3√2-2)=18-12√2+4-12√2+8+1
f(3√2-2)=31-24√2
wyznacz wartość funkcji F(x)=-x^2-4x+1 dla x=3 razy piarwiastek z 2 -2
f(x) = -x² -4x +1
dla x = 3√2 -2
f(3√2 -2) = -(3√2 -2)² - 4( 3√2 -2) +1
Korzystam ze wzoru :
(a-b)²= a²-2ab+b²
f(3√2 -2) = -[(3√2)² - 2*3√2 *2 + 2² ] - 12√2 + 8 +1
f(3√2 -2) = -[ 9*2 - 12√2 +4] -12√2 +9
f(3√2 -2) = -[22 -12√2 ] -12√2 +9
f(3√2 -2) = - 22 +12√2 -12√2 +9
f(3√2 -2) = - 13