Question

wyznacz trzeci, czwarty, ósmy i 2k-3 wyraz ciągu opisanego wzorem ogólnym a) an= -3n+7 b) bn- (-1) do n+1

Answer 1

a)

an= -3n+7

a3= -3*3+7 = -9+7 = -2

a4= -3*4+7 = -12+7 = -5

a8= -3*8+7 = -24+7 = -17

a(2k-3)= -3*(2k-3)+7 = -6k+9+7 = -6k+16

b)

bn = (-1)^(n+1)

b3 = (-1)^(3+1) = (-1)^4

b4 = (-1)^(4+1) = (-1)^5

b8 = (-1)^(8+1) = (-1)^9

b(2k-3) = (-1)^(2k-3+1) = (-1)^(2k-2)