Wyznacz rownanie okregu o srodku S=(3,-2) stycznego do osi OY
(x-a)²+(y-b)²=r²
a=3, b=-2, r=|x|=3
(x-3)²+(y+2)²=9
S= (3; -2)
Xs = 3
Ys = -2
IrI = 3
Równanie okręgu:
(X-Xs)² + (Y-Ys)² = r²
(x-3)² + (y+2)² = 9
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(x-a)²+(y-b)²=r²
a=3, b=-2, r=|x|=3
(x-3)²+(y+2)²=9
S= (3; -2)
Xs = 3
Ys = -2
IrI = 3
Równanie okręgu:
(X-Xs)² + (Y-Ys)² = r²
(x-3)² + (y+2)² = 9
-----------------------