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(x-3)do kwadratu+(y-5)do kwadratu i prostej x+y=4
Brak promienia w równaniu okregu aby można prawidlowo rowiazać zadanie!!!
x+y=4
y = 4 -x
(x -3)² + (y -5)² = r²
y = 4-x
(x-3)² + (4-x-5)² = r²
y = 4-x
x² -6x +9 + (-x-1)² = r²
y = 4-x
x² -6x +9 + x² +2x +1 = r²
y = 4-x
2x² -4x +10 = r²