wyznacz miejsce zerowe funkcji f(x)=x - 4x^{2} +3x
f(x) = x³-4x²+3x
f(x) = x(x²-4x+3)
x = 0 ∨ x²-4x+3=0
x²-4x+3=0
Δ = 16-4·3·1
Δ = 4
√Δ = 2
x₁ = (4-2)/2 = 1
x₂ = (4+2)/2 = 3
Miejsca zerowe funckji: x∈{0,1,3}
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f(x) = x³-4x²+3x
f(x) = x(x²-4x+3)
x = 0 ∨ x²-4x+3=0
x²-4x+3=0
Δ = 16-4·3·1
Δ = 4
√Δ = 2
x₁ = (4-2)/2 = 1
x₂ = (4+2)/2 = 3
Miejsca zerowe funckji: x∈{0,1,3}