Wyznacz miejsca zerowe funkcji y = x³ -7x² - 2x + 14
y = x³-7x²-2x+14 = 0
x²(x-7) - 2(x-7) = 0
(x²-2)(x-7) = 0
(x+√2)(x-√2)(x-7) = 0
x+√2 = 0 => x = -√2
lub
x-√2 = 0 => x = √2
x-7 = 0 => x = 7
Odp. x = -√2 v x = √2 v x = 7
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y = x³-7x²-2x+14 = 0
x²(x-7) - 2(x-7) = 0
(x²-2)(x-7) = 0
(x+√2)(x-√2)(x-7) = 0
x+√2 = 0 => x = -√2
lub
x-√2 = 0 => x = √2
lub
x-7 = 0 => x = 7
Odp. x = -√2 v x = √2 v x = 7