January 2019 1 8 Report
Wyznacz miejsca zerowe funkcji f(x)= -2x+b , jeśli liczba b spełnia równanie:


(√2-b)²- (b-2√2)² = -6
( (\frac{1}{2}b +2)(2- \frac{1}{2}b)+(1+ \frac{1}{2}b)^{2} =0
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