wyznacz masy molowe następujących związków chemicznych KNO 3 Mg(OH)2,FeS,H4P2O7 dokonaj odpowiednich obliczeń
KNO3 = 39,1g + 14,01g + 3*16g = 101,11g/mol
Mg(OH)2 = 24,31g + 2*16g + 2*1,01g = 58,33g/mol
FeS = 55,85g + 32,07g = 87,92g/mol
H4P2O7 = 4*1,01g + 2*30,97g + 7*16g = 177,98g/mol
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KNO3 = 39,1g + 14,01g + 3*16g = 101,11g/mol
Mg(OH)2 = 24,31g + 2*16g + 2*1,01g = 58,33g/mol
FeS = 55,85g + 32,07g = 87,92g/mol
H4P2O7 = 4*1,01g + 2*30,97g + 7*16g = 177,98g/mol