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2x = y-4
y² = 50x
2x+4 = y
y² = 50x
(2x+4)² = 50x
4x² + 16x + 16 = 50x
4x² - 34x + 16 = 0
2x² - 17x + 8 = 0
√Δ = 15
x = 0,5 ∨ x = 8
y = 4 ∨ y = 20
Warunki zadania spełniają dwie pary liczb: (0,5; 4) oraz (8; 20)