wyznacz liczbe x^{-2} jesli wiadomo ze
x=[16¼+3⁻¹]/4=[16¼+⅓]/4=16⁷/₁₂×¼=¹⁹⁹/₁₂×¼=¹⁹⁹/₄₈
x⁻²=1/x²
[¹⁹⁹/₄₈]⁻²=[⁴⁸/₁₉₉]²=²³⁰⁴/₃₉₆₀₁
x =[16 1/4 +3^(-1)]/4 =(16 1/4 +1/3)*1/4 =(16 3/12 + 4/12)*1/4 =
= (16 7/12)*1/4 =119/12 *1/4 =119/48
x^(-2) = 1/x^2
(199/48)^(-2) =(48/199)^2 = 2304/39601
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x=[16¼+3⁻¹]/4=[16¼+⅓]/4=16⁷/₁₂×¼=¹⁹⁹/₁₂×¼=¹⁹⁹/₄₈
x⁻²=1/x²
[¹⁹⁹/₄₈]⁻²=[⁴⁸/₁₉₉]²=²³⁰⁴/₃₉₆₀₁
x =[16 1/4 +3^(-1)]/4 =(16 1/4 +1/3)*1/4 =(16 3/12 + 4/12)*1/4 =
= (16 7/12)*1/4 =119/12 *1/4 =119/48
x^(-2) = 1/x^2
(199/48)^(-2) =(48/199)^2 = 2304/39601