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3c+x+2=3c(c+x)
3c+x+2=3c²+3cx
3c²+3cx-3c-(x+2)=0
3c²+(3x-3)c-(x+2)=0
Δ=(3x-3)²+4*3(x+2)=9x²-18x+9+12x+24=9x²-6x+33
c=1/6*(3-3x-√(9x²-6x+33)) v c=1/6*(3-3x+√(9x²-6x+33))