wysokosc stozka ma dlugosc 6 i jest rowna polowie jego srednicy.oblicz objetosc i pole powierzchni calkowitej stozka
h = d/2 = r
V = 1/3 * π * r² * h
V = 72π(j³)
l = √(h² + r²)
l = 6√2(j)
Pc = π * r² + π * r * l = 36π + 36√2π = 36(π + √2π)(j²)
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h = d/2 = r
V = 1/3 * π * r² * h
V = 72π(j³)
l = √(h² + r²)
l = 6√2(j)
Pc = π * r² + π * r * l = 36π + 36√2π = 36(π + √2π)(j²)