Wysokość stożka h= 3 √2 cm, a promień podstawy r=3 cm. Oblicz długość tworzącej stożka.
h=3pierw z 2
r = 3cm
l=?
h^{2} +l^{2}=r^{2}
18-9=l^{2}
l=3
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h=3pierw z 2
r = 3cm
l=?
h^{2} +l^{2}=r^{2}
18-9=l^{2}
l=3