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x=6cm to, 12/x=3cm
y=9cm to 1/2y=9/2 cm
Pp=1/2xy=1/2·6·9=27cm²
V=1/3Pp·H=1/3·27·10=90cm³
z pitagorasa
3²+(9/2)²=a²
9+81/4=a²
9+20,25=a²
a²=29,25
a=√(29,25)=√(117/4)=3√13/2--->bok rombu
kazdy romb jest rownoleglobokiem czyli Pp=ah
27=3√13/2 ·h
27=3h√13/2 /·2
54=3h√13
h=54/3√13=18/√13 cm --->wysoksoc rombu
promien kola wpisanego w romb r=1/2h=1/2·18/√13=9/√13cm
z pitagorasa
r²+H²=hs²
(9/√13)²+10²=hs²
81/13+100=hs²
hs²=106³/₁₃
hs=√(106³/₁₃)=√(1381/13)cm --->wysokosc sciany bocznej ostroslupa
Pb=4·1/2·a·hs=2ahs=2·3√13/2·√(1381/13)=3√1381 cm²
pole calkowite ostroslupa
Pc=Pp+Pb=27+3√1381=3(9+√1381)cm²