wyrazenie pierwiastek z 3 przez pierwiatek z szesciu odjąc trzy jest równe :
PROSZE OBLICZENIA BO NIE DAM PINKTÓW~~
√3 : (√6 - 3) = √3 * (√6 + 3) : [(√6 - 3)(√6 + 3)] = (√18 + 3√3) : (6 - 9) = (√9 * √2 + 3√3) : (-3) = (3√2 + 3√3) : (-3) = [3(√2 + √3) :(-3) = -√2 - √3
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√3 : (√6 - 3) = √3 * (√6 + 3) : [(√6 - 3)(√6 + 3)] = (√18 + 3√3) : (6 - 9) = (√9 * √2 + 3√3) : (-3) = (3√2 + 3√3) : (-3) = [3(√2 + √3) :(-3) = -√2 - √3