Question

Wyrażennia algebraiczne
y+[2y-1]=
2[x-1]=
1+x+1=
2[y-1]+y=
4+y+5-y=
2[x-2]-x=
y+2y=
7[x+3]-6[x+4]=
2[y+1]+[y-1]=
5[x+4]-[5x-3]=

Answer 1

Y+[2y-1] = y+2y-1 = 3y-1
2[x-1]=2x-2
1+x+1=2+x
2[y-1]+y=2y-2+y=3y-2
4+y+5-y=9
2[x-2]-x=2x-4-x=x-4
y+2y=3y
7[x+3]-6[x+4]=7x+21-6x-24=x-3
2[y+1]+[y-1]=2y+2+y-1=3y-1
5[x+4]-[5x-3]=5x+20-5x+3=23

Answer 2

A) y+[2y-1]=0
y+2y-1=0
3y=1 /:3
y=1/3
b)  2[x-1]=0
2x-2=0
2x=2 /:2
x=1
c) 1+x+1=0
x=-1-1
x=-2
d) 2(y-1)+y=0
2y-2+y=0
3y=2 /:3
y=2/3
e) 4+y+5-y=0
y-y=-4-5
0≠-9
f) 2[x-2]-x=0
2x-4-x=0
2x-x=4
x=4
g) y+2y=0
3y=0 /:3
y=0
h) 7[x+3]-6[x+4]=0
7x+21-6x-24=0
x=-21+24
x=3
i) 2[y+1]+[y-1]=0
2y+2+y-1=0
2y+y=-2+1
3y=-1 /:3
y=-1/3
j) 5[x+4]-[5x-3]=0
5x+9-5x+3=0
5x-5x=-9-3
0≠-12