wykonaj działania i przedstw otrzymany wielomian w jak najprostszej postaci 2(x^3-2x+4)-(x-3)(x^2+5x-4)=
2(x³-2x+4)-(x-3)(x²+5x-4)=2x³-4x+8-(x³+5x²-4x-3x²-15x+12)=
=2x³-4x+8-(x³+2x²-19x+12)=2x³-4x+8-x³-2x²+19x-12=
=x³-2x²+15x-4
2(x^3-2x+4)-(x-3)(x^2+5x-4)=2x^3-4+8-(x^3+5x^2-4x-3x^2-15x+12)=2x^3-4x+8-(x^3+2x^2-19x+12)=2x^3-4x+8-x^3-2x^2+19x-12=x^3-2x^2+15x-4Pozdrawiam :)
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2(x³-2x+4)-(x-3)(x²+5x-4)=2x³-4x+8-(x³+5x²-4x-3x²-15x+12)=
=2x³-4x+8-(x³+2x²-19x+12)=2x³-4x+8-x³-2x²+19x-12=
=x³-2x²+15x-4
2(x^3-2x+4)-(x-3)(x^2+5x-4)=2x^3-4+8-(x^3+5x^2-4x-3x^2-15x+12)=2x^3-4x+8-(x^3+2x^2-19x+12)=2x^3-4x+8-x^3-2x^2+19x-12=x^3-2x^2+15x-4
Pozdrawiam :)