Question

wyłącz czynnik przed pierwiastek; pierwiastek z 32,75,40 pierwiastek sześcienny z40,96,243

Answer 1

√32 = √16 x √2 = 4√2

√75 = √3 x √25 = 5√3

√40 = √4 x √10 = 2√10

 

∛40 = ∛8 x ∛5 = 2∛5

∛96 = ∛8 x ∛12 = 2∛12

∛243 = ∛27 x ∛9 = 3 x ∛9

 

 

 

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Litterarum radices amarae sunt, fructus iucundiores

 

Pozdrawiam :)

Answer 2

√32 =√(16*2) = √(4² * 2) = 4√2

√75=√(25*3)=√(5²*3)=5√3

√40 = √(4*10)=√(2²*10)=2√10

 

∛40 = ∛(8*5)=∛(2³*5)=2∛5

∛96=∛(8*12)=∛(2³*12)=2∛12

∛243=∛(27*9)=∛(3³*9)=3∛9