wychodząc od węgla lub węglika glinu otrzymaj 3 amidy dowolnych kwasów (w tym ma być 1 amid z pierścieniem- benzen)
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Al4C3 + 12HCl = 3CH4 + 4AlCl3
CH4 + Cl = CH3Cl + HCl
CH3Cl + NaOH = CH3OH + NaCl
CH3OH + CuO = HCHO + Cu + H2O
HCHO + 2Cu(OH)2 = HCOOH + Cu2O + 2H2O
HCOOH + NH3 = HCONH2 + H2O
2CH3Cl + Na = CH3CH3 + 2NaCl
CH3CH3 + Cl2 = CH3CH2Cl + HCl
CH3CH2Cl+ NaOH = CH3CH2OH + NaCl
CH3CH2OH + CuO = CH3CHO + Cu + H2O
CH3CHO + 2Cu(OH) = CH3COOH + Cu2O + 2H2O
CH3COOH + NH3 = CH3CONH2 + H2O
C + H = C2H2
3C2H2=C6H6
C6H6 + CH3Cl = C6H5CH3 + HCl
C6H5CH3 + Cl2 = C6H5CH2Cl + HCl
C6H5CH2Cl + NaOH = C6H5CH2OH + NaCl
C6H5CH2OH + CuO = C6H5CHO + Cu + H2O
C6H5CHO + 2Cu(OH)2 = C6H5COOH + Cu2O + 2H2O
C6H5COOH + NH3 = C6H5CONH2 + H20