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b = 1,4
3 x 1 = 3 (nieparzysta )
5 x 1 = 5 (nieparzysta)
Parzyste :
2x1=2
2x4=8
3x4=12
4x1=4
4x4=16
5x4=20
Odp:. W zbiorach można znaleźć 2 pary .
Więc 2 pary
1*3
1*5