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P₁=4m*0,8m=3,2m²
P₂=(6m+0,8m * 0,8m)*0,8m=7,6m*0,8m=6,08m²
Pc=2*P₁+2*P₂
Pc=2*3,2m² + 2*6,08m²=6,4m²+12,16m²=18,56m²
Pole powierzchni tej sciezki wynosi 18,56m².