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Potrzebje rozwiązania zadania
Polecenie brzmi:
2.4 Zapiszz liczby w postaci ulamkow zwyklych
b) 2,24 0,1(5) 13,2(4) 1,2(6)
c)3,(15) -2,0(1) 5,3(2) 3,2(9)
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0,1(5) = 0,15555555555 ..
.x = 0,15555555555...
10x = 1,55555555555
10 x - x = 1,4
9 x = 1,4
x = 1,4 : 9 = 14/90
x = 7/45
13,2(4) = 13,2444444444...
x = 13,244444444444....
10x = 132,4444444444...
10 x - x = 119,2
9 x = 119,2
x = 119,2 / 9 = 1192/90 = 596/45
1,2(6) = 1,266666666666...
x = 1,2666666666...
10 x = 12,666666666...
10 x - x = 11,4
9 x = 11,4
x = 11,4 / 9 = 114/90 = 57/45 = 19/15
c) X = 3,1515151515.../x100
100x = 315,151515
100x - x = 312
99x = 312/ : 99
x = 312/99 = 104/33
x = -2,011111... / x100
100x = -201,1111111
100x - 10x = -191
90x = -191/ :90
x= -191/90
x=5,3222222.../ x 100
100x = 532,22222
100x - 10x = 479 (bo 532,2222... - 53,2222... = 497)
90x = 479/ :90
x = 479/90
x=3,29999999... / x100
100x = 329,999999
100x - 10x = 297
90x = 297 / :90
x = 11/10