Odp. w załączniku
(x+1)/(2x+6)-9/(x²-9)=(x-2)/(2x-6)
zał. x≠-3 i x≠3
(x+1)/2(x+3)-9/(x-3)(x+3)=(x-2)/2(x-3) /*2(x-3)(x+3)
(x+1)(x-3) -9*2=(x-2)(x+3)
x²-3x+x-3-18=x²+3x-2x-6
-2x-21=x-6
-2x-x=-6+21
-3x=15 /:(-3)
x=-5
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Odp. w załączniku
(x+1)/(2x+6)-9/(x²-9)=(x-2)/(2x-6)
zał. x≠-3 i x≠3
(x+1)/2(x+3)-9/(x-3)(x+3)=(x-2)/2(x-3) /*2(x-3)(x+3)
(x+1)(x-3) -9*2=(x-2)(x+3)
x²-3x+x-3-18=x²+3x-2x-6
-2x-21=x-6
-2x-x=-6+21
-3x=15 /:(-3)
x=-5