wiedząc że
2/x+3/y+4/z=7/3
(x+2)/x+(3+y)/y+(4+z)/z=
=x/x+2/x+3/y+y/y+4/z+z/z=
= 1+2/x+3/y+1+4/z+1=
=3+(2/x+3/y+4/z=
=3+7/3=3+2 1/3=
=5 1/3
Pozdrawiam :)
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2/x+3/y+4/z=7/3
(x+2)/x+(3+y)/y+(4+z)/z=
=x/x+2/x+3/y+y/y+4/z+z/z=
= 1+2/x+3/y+1+4/z+1=
=3+(2/x+3/y+4/z=
=3+7/3=3+2 1/3=
=5 1/3
Pozdrawiam :)