wiedzac, ze n^2+n-1=0 oblicz n^3+2n^2+2012
n³+2n²+2012 = n³+n²+n²+2012 =
= n(n²+n)+n²+2012 =
n²+n-1 = 0
n²+n = 1
= n·1+n²+2012 =
= n²+n+ 2012 =
= 1+2012 =
= 2013
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n³+2n²+2012 = n³+n²+n²+2012 =
= n(n²+n)+n²+2012 =
n²+n-1 = 0
n²+n = 1
= n·1+n²+2012 =
= n²+n+ 2012 =
= 1+2012 =
= 2013
======