wartośc wyrażenia 25*(1,5)do podegi 2 +4*5do potego 0
prosze aby ktos obliczyl !:)
i ile jest pierwiastek z 128 ?
25*(1,5)² + 4*5⁰ = 25 * (3/2)² + 4*1 = 25*9/4 + 4 = 225/4 + 4 = 56 1/4 + 4 = 60 1/4
√128=√(64*2) = 8√2
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25*(1,5)² + 4*5⁰ = 25 * (3/2)² + 4*1 = 25*9/4 + 4 = 225/4 + 4 = 56 1/4 + 4 = 60 1/4
√128=√(64*2) = 8√2