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P = 120cm²
P = a × h/2
120 = 16 × h /2 /×2
240 = 16 × h /16
h = 15
Z twierdzenia Pitagorasa obliczmy bok BC:
BC = AC
(½AB)² + h² = (BC) ²
8² + 15² = (BC) ²
289 = (BC) ² / √
BC = 17
AC = 17
Obwód:
2 × 17 + 16 = 50 cm