W trojkacie rownoramiennym ABC boki maja dlugosc: |AC| = |BC| = 10cm, |AB| = 16cm. Punkty D i E sa odpowiednio srodkami ramion AC i BC tego trojkata. Wyznacz obwod trojkata AED.
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|AC| = |BC| = 10cm
|AB| = 16cm
|DE|=½|AB|=½·16=8cm
|AD|=½|AC|=½·10=5cm
Odcinek |AE| to środkowa boku |BC|
L=8+5+3√17=13+3√17cm