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|AB|=x
|CD|=x
|CE|=h
P ABC = 9cm²
Z trójkąta ABC wyliczamy h, ktore również jest wysokościa trapezu:
P ABC = ½*3x*h
9 = ½*3x*h
h=6/x
Pole trapezu:
P ABCD = ½*(3x+x)*6/x = ½*4x*6/x = 12cm²