W trapezie jedna a podstawa jest 2 razy dłuższa niż druga, wysokość ma 8 cm a pole wynosi 54 cm2 .Oblicz długość podstaw tego trapezu NA DZIŚ!!
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a = 2x
b = x
h = 8cm
P = 54cm^2
P = 1/2 * (a +b) * h
54 = 1/2 * (2x + x) * 8
54 = 4 * 3x
54 = 12x
x = 54 : 12
x = 54/12 = 27/6 = 9/2 = 4,5
a = 2x = 2 * 4,5 = 9cm
b = x = 4,5cm