W tlenku azotu stosunek azotu do tlenu wynosi 7:4 Ustal wzór tego związku.
7 28
- = -
4 16
mN = 14u
28 : 14 = 2
mO = 16u
16 : 16 = 1
N2O
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7 28
- = -
4 16
mN = 14u
28 : 14 = 2
mO = 16u
16 : 16 = 1
N2O