September 2019 0 144 Report
W równoloegloboku ABCD dane są wierzchołki A=(0,6) , B=(3,0) C=(-4,0) .Wobec tego bok CD zawiera się w prostej o równaniu

A. y=-2x+8
B. y=-2x-8
C. y=2x+8
D. y= 2x-8
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