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Masa użytego tlenu: 160-128=32g
128:32
4:1
2Cu + O2----->2CuO
128g Cu + xg O2 = 160g CuO
x = 160 - 128
x = 32g O2
mCu : mO = 2*64u : 2*16u
mCu : mO = 128 : 32
mCu : mO = 4 : 1