W nacyzniu jest 1kg wodz o temp 20 K. Oblicy ile wodz o temp. 100K nalezz dola aby temp. końcowa wynosiła 60K ??
m1= 1 kg
t1= 20K
m2=?
t2 = 100K
t3= 60 K
m1(t3-t1) = m2(t2-t3)
1kg*40K = m2*40K
m2=1kg
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m1= 1 kg
t1= 20K
m2=?
t2 = 100K
t3= 60 K
m1(t3-t1) = m2(t2-t3)
1kg*40K = m2*40K
m2=1kg