W ciągu geometrycznym wyraz a2=-4 a wyraz a3=4 > Oblicz S40 i S101.
proszę
q=a₃/a₂=4/-4
q=-1
.........................
a₂=a₁q
-4=a₁×(-1)
a₁=4
...............
S₄₀=a₁×(1-q⁴⁰)/(1-q)
S₄₀=4[1- (-1)⁴⁰]/(1+1)=0
S₁₀₁=a₁×[1-q¹⁰¹]/(1-q)
S₁₀₁=4 [ 1-(-1)¹⁰¹] / (1+1)=4
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q=a₃/a₂=4/-4
q=-1
.........................
a₂=a₁q
-4=a₁×(-1)
a₁=4
...............
S₄₀=a₁×(1-q⁴⁰)/(1-q)
S₄₀=4[1- (-1)⁴⁰]/(1+1)=0
S₁₀₁=a₁×[1-q¹⁰¹]/(1-q)
S₁₀₁=4 [ 1-(-1)¹⁰¹] / (1+1)=4